Hi there!

In the rule book pg 359 "Damaging a Horde" it is said that weapons that inflict explosive damage (like bolters) gain one additional hit against hordes...

so it means you take a single shoot and roll 2 damage rolls...that`s clear, but what about full auto? 8 hits ( 4 hits + 4 times from explosion)?

and what if you load your standart bolter with metal storm rounds and fire on full auto? Blast (2) said it hit a horde two times...

so does it count as 1 hit from standart damage + 1 hit from explosion + 2 hits from blast multiplied with full auto (x4) meaning you hit the horde for a damage of 16(!) to the magnitude ?

MAY THE ALLFATHER BE WITH YOU BROTHER CIPHIAS!!!!!!!!!!!!.......ACTUALLY YOU WILL JUST GET ONLY "1" EXTRA HIT OUT OF THE WEAPON WITH E(X)PLOSIVE DAMAGE, NOT 1 PER HIT BROTHER....THIS MEANS THAT WITH YOUR STANDAR BOLTER THE MAXIMUM DAMAGE WOULD BE:

S__1HIT + 1PER E(X)PLOSIVE DAMAGE

2__3HIT + 1 PER E(X)PLOSIVE DAMAGE

4__5HIT + 1 PER E(X)PLOSIVE DAMAGE

I HOPE I HELPED BROTHER.......FOR RUSS AN THE ALL FATHER!!!!!!!!!!!!!!!!

Don't forget, you score 4 hits on full auto if you succeed with 3 or more Degrees of Success (i.e. you roll 30+ under the value you had to roll to hit ).

Explosive, as has been said above, only adds an additional magnitude hit. Blast(2) does multiply, but only the hits you actually do. So, if you do score 4 hits with your bolter on full auto, the horde loses 2x4+1 = 9 magnitude. Which is already quite cool.

Ciphias said:

Let's say you attack with a Bolter and roll 2 Degrees of Success. That means 3 shots hit (1 + 2 extra hits). Normally horde magnitude would be diminished by 3 but due to X damage type it is reduced by 4.

Alex