The card air soldier say's that you must kill it before any other dark cards, because all damage is done in one battle does that make it so that if you have an air soldier and another dark card they have to kill the air soldier in one battle and then the other dark card on their next turn because all dark cards die at the same time

Haha, this is a very common question actually.

You can kill all dark heartless on the world including air soldier in one turn. As you know, when you attack dark cards, the total of all the power you are dealing against them adds up, as long as you destribute enough damage to kill the air soldier BEFORE you distribute to other darks, you can take out them all.

PS

Playing 2 air soldiers doesnt create an infinite lock making them unkillable. Just have to kill the 2 first before the others.

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#55 Of The Five Of Spades

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so your saying that all the damage does not happen at the same time

Basically, the way it works is this:

You put an Air Soldier on your opponent's world, along with a Shadow. Yadda yadda, you finish your turn. Your opponent then starts their turn, 'n decides to attack. Say he has the basic Sora lvl 1, which has 4 attack power. He then adds a Divine Rose to the attack, makin his attack power a 9. Since Air Soldier's effect kicks in (along with the +1 POW boost from Shadow), all the damage is directed to Air Soldier. 8 of the 9 attack power hits, killin the Air Soldier. The remainin 1 attack power is/can be directed to the Shadow, which doesn't kill it. However, if your opponent had also play'd a Lady Luck (+4 attack power) durin the turn, then his total attack power would've been 13, which would've been enough to kill off both the Air Soldier 'n the Shadow.

Now, with two Air Soldiers (use same example as above, except add another Air Soldier), your opponent's attack power of 13 (Sora+Divine Rose+Lady Luck) would all have been directed towards the two Air Soldiers (both POWs of 8 with Shadow's effect). One of the Air Soldiers would effectively die, while the other would take the remaining 5 damage, which wouldn't be enough to kill it this turn. Say your opponent then passes, seein they can't beat the Heartless on their world. You take your turn 'n do your thing. Your opponent's turn pops up 'n the Heartless on their world (the Air Soldier 'n Shadow) are back at full POW (8 'n 5, with Shadow's effect). Your opponent would have to attack once again 'n kill off the Air Soldier before they would be able to begin to hurt the Shadow on the world (see above example). If your opponent were able to have gain'd 21+ attack power in their previous turn when the three Heartless were on their world, they would've been able to advance to the next world, or do whatever they had desired, due to that bein the total amount necessary to destroy all three of the Heartless.

Does this make sense now?

yes thank you