Hello,
I presonally like the idea of the mechanics of the opposed test, but I have the impression it won't work when two high skilled contendants are opposed.
Since me and my party are quite new in the 3rd edition system, I have not myself the oportunity to face the situation. Nonetheless, here is my point.
The chances of success in an opposed test improve dramatically as the skill of the active participant improves, while from my point of view it should always be related to the ratio between the two skills, the one from the active character and the one of the passive character.
Let's suppose that a thief with Ag4 tries to sneak pass a guard with Int4. Supose that the thief has trained one level on stealth and he has one fortune die in Ag, let's also supose he is one level deep in conservative stance. At the same time the guard has trained one level on Observation and the GM decides to spend on misfortune die from the Cunning dice pool of the guard. The dice pool will be then three characteristic dice, one conservative stance dice, one fortune dice, one expertise dice, two challenge dice and two misfortune dice. With this pool the success chances of the opposed test are roughly 33%.
Let's suppose now that the same two characters meet years later, when both of them are much more experienced. Now the thief has Ag6, three fortune dice in Ag, three trained levels on stealth and he is 3 levels deep in conservative stance. At the same time, the guard has Int6, three trained levels of Observation etc...The GM decides to spend 3 extra misfortune dices comming from the Cunning dice pool of the guard. The total dice pool will be composed of three characteristic dice, three conservative stance dice, three fortune dice, three expertise dice, two challenge dice and four misfortune dice. With this pool, the success chances of the opposed test are more than 90%.
To mee it looks very wierd! I am doing something wrong? Can anyone give to me a valid interpretation of this? Or a good house rule to correct it?
Thank you!