HEllo!
I've got a question about how does the investigators attack work.
I've read the rulebook and the FAQ, but i dont understand something...
From rulebook:
When the players accumulate a
total number of successes equal to the number of players
(including any players that were eliminated from the
game), remove one doom token from the Ancient One’s
doom track and reset their cumulative successes to zero.
From FAQ:
A: To defeat the Ancient One, the players must do a total
number of successes equal to the number of players multiplied
by the number of doom tokens on the Ancient One.
So, if 4 players are facing Yig (doom track of 10), they
need 40 successes to win. For every 4 successes they do,
they remove 1 doom token to track their progress. If the
investigators get 9 successes in the first round of combat,
they would remove 2 doom tokens, and 1 success would
carry over to the next round of combat.
So what means "reset their cumulative succes to zero"?
With two investigator, we need two successes to remove one doom token. Its clear. But what happens if the first investigator roll six successes? For the first two successes, they can remove one doom token, than "reset their cumulative succes to zero" means, they lost the other four successes? Or with this roll, they can remove three tokens?
Thanks for your help
(and sorry for my english, i havent use it for years...)