The Laughing Storm and Threat from the East

By Ivengar, in 2. AGoT Rules Discussion

So if I have a standing Laughing storm. I and play Threat from the east, do I.....

A) Draw 3 cards and then discard nothing.

B) Not discard 3 random cards and then draw 3 cards.

C) do nothing becase the Laughing Storm is stoping me from discarding cards there for the plot effect does not go off for me.

I guess what my question is, is the discarding of cards part of the "cost" of drawing the 3 cards or is it just an effect and can be ignored by TLS?

Thanks!

Ivengar said:

So if I have a standing Laughing storm. I and play Threat from the east, do I.....

A) Draw 3 cards and then discard nothing.

B) Not discard 3 random cards and then draw 3 cards.

C) do nothing becase the Laughing Storm is stoping me from discarding cards there for the plot effect does not go off for me.

I guess what my question is, is the discarding of cards part of the "cost" of drawing the 3 cards or is it just an effect and can be ignored by TLS?

Thanks!

My understanding of this scenario is this.

A) You draw 3 cards and then discard nothing.

OR

B) Not discarding 3 random cards prevents you from drawing 3 cards.

Option A does not require you to discard 3 cards in order to draw 3 cards. So you may do this even if you have less than 3 cards in your hand.

For option B you MUST discard 3 random cards in order to draw 3 additional cards. This also means if you have less than 3 cards, you will not be able to draw 3 more.

Bomb is correct. The key word on Threat from the East is "then." If part of an ability is linked to a previous part with the word "then," it's application is always dependent on the successful resolution of what preceded it. But the first part of the ability will resolve regardless of whether the second part can be resolved successfully. It's a one-way dependency.

But the part before the "then" must be resolved successfully by BOTH players, or that condition must be checked separately by all players?

For example if I am able to discard 3 cards at random, but my opponent can''''t (he has only 2 cards in hand), who will draw?

A) only me, because I met the conditions

B) Noboby draws because not all players satisfied the condition

Originally, this was checked individually. But at some point, Damon ruled that it was "all or none." All players must draw or discard 3 cards (each) before the part before the "then" is considered successful.

Plot Text: "When revealed, you choose one:
- Each player draws 3 cards and then discards 3 random cards from hand.
- Each player discards 3 random cards from hand and then draws 3 cards.

The plot wording is such that EACH player must successfully accomplish the first part before the part after THEN can resolve properly. No one will draw cards in the example you provide. The part after THEN effectively fizzles

ok, thanks guys!

this is an old thread but if i only have 2 cards and i pick discard first then nothing will happen?

johnn0411 said:

this is an old thread but if i only have 2 cards and i pick discard first then nothing will happen?

If you choose "discard" first, everyone will discard as many of the 3 cards as they can. And if any player discarded fewer than 3 cards, no one gets to draw.

Does this mean that every time a discard effect triggers (or is triggered, thus not being a cost) that states "discard X cards" has implied the wording "discard UP TO X cards"?

implicit, not implied. sorry.

Yes, just like every draw effect is treated as "up to" X cards. If you have already drawn 1 card, for example, and you play a "draw 3" effect, you get 2 cards before hitting the draw cap.

This is because cards are considered to be drawn or discarded individually.