Hiya.
I'm intrigued by the concept of a bounty-hunter style character, who is armed with a multitude of pistols; as such, I'm trying to work out exactly how Full-Auto with two pistols works, but the rules are a bit contrary.
According to the rules:
1. Full-Auto burst action (page 239) says that you can fire two pistols, one in each hand, with this action. See Two Weapon Fighting, page 246.
2. Two weapon fighting, page 246, says that attacks made with the off-hand are at -20.
3. Two weapon fighting, page 246, says that if you attack you can use the Multiple Attacks action to attack with both weapons, but both are at -20.
Here's where I get confused:
1/2: Full-auto burst gives you +20 to hit, so are we effectively saying that any sort of BS penalty to the off-hand will be negated by this? Doesn't this make full-auto totally awesome, as you're +20 primary, +0 secondary?
1/3: is firing two autopistols on full-auto a "Full Auto Burst" action, or a "Multiple Attacks" action - and does this distinction make any difference to the -20 to hit with both weapons? It appears to me that firing both pistols gives you the -20 BS to each - which is why you're directed to two-weapon fighting page - but the RAW seems to imply that it's only the "Multiple Attacks" action that attracts the penalty, and that's not what you're doing (you're donig the "Full-Auto action").
2/3: Is the -20 off-hand penalty cumulative with the -20 penalty for firing both guns? So, if you're firing both weapons, is it -20 to each, or is it -20 primary, -40 off-hand?
I'm aware that Ambidextrous and Gunslinger will change the numbers involved, I'm just trying to get the rules sorted for now.
Basically, the character image I have in my head is sort of like a cross between the bald guy on page 110 and War Machine from Iron Man; but, I'm slightly concerned (or hopeful, depending upon my mood...) that getting forearm mounts for my guns, thus not needing to reload ever, totally abuses the Full Auto rules...
Cheers,