Explanation on Chaotic Force

By topacesteve, in Imperial Assault Rules Questions

So the card reads...each player chooses up to 3 figures. And EACH figure suffers strain equal to accuracy.

Up to 3 means that each player should strictly choose 3 figures if available and if i.e. he is only left with 2 figures only then

can he choose 2?

Up to 3 means each player can either select 0, 1, 2 or 3 figures from the opponent's list, then they roll the die and see how much strain they hurt.

I dont understand why would i ever choose 1 or 0 figures from my opponent list...

It would be more meaningful if i chose only 1 figure for my opponent but was hit 3x (green accuracy) or 2 figures (the first 2x accuracy , the second, 1x accuracy)

Also the card states : Figures . not enemy figures...

Chaotic%20Force.png

Step 1: "Each player chooses up to 3 figures." This means you can choose 0, 1, 2, 3 figures in the game, wether they be yours or from your opponent's list, but i don't think you wanna hurt your own figures.
Step 2: "Roll 1 green die." You only get to roll the die, that roll will influence all chosen targets by both players.
Step 3: "Each of those figures suffers strain equal to the Accuracy result."

3 hours ago, topacesteve said:

I dont understand why would i ever choose 1 or 0 figures from my opponent list...

If the opponent only has 1 figure left.