On 24.4.2017 at 10:20 PM, JRosen9 said:What if you compare with both the the highest and lowest player and only pay once?
Example:
Player A Bids 5
Player B Bids 4
Player C Bids 3
Player D Bids 2
Player E Bids 1
Player A compares to himself and Player E. He Gains 0 honor (5-5 = 0) and Loses 4 Honor (5-1 = 4) for a net of 4 honor loss
Player B compares to Player A and E. He gains 1 honor (5-4=1) and loses 3 honor (4-1=3) for a net of 2 honor loss.
Player C compares to Player A and E. He gains 2 honor (5-3=2) and loses 2 honor (3-1=2) for a net of 0 honor change
Player D compares to Player A and E. He gains 3 honor (5-2=3) and loses 1 honor (2-1=1) for a net of 2 honor gain
Player E compares to Player Player A and himself. He gains 4 honor (5-1=4) and loses 0 (1-1=0) for a net of 4 honor gain.
I see no reason why this shouldn't work
This approach has two flaws. lets say you have only four player and ever resolt fro 1-4, which means the average ould come down to a number that lies between 2 and 3, so would players no suddenly get half point or lose half points? Or do you then add another rule on how things should be rounded and thus make certain choices better than others and that on top of the already high book keeping time with that approach, which seems to me not much fun.
And the second flaw is that it makes the average of 3 always the best bet to be, where you lose the least points while still getting a decent amount of cards, while the risk of taking only one card is not rewarded properly with plenty of honour, and the option to take five cards is also not as punishing in regards how much honour is lost, which could screw the game balance quite a bit.
So, overall I think that would be a terrible solution.
