Hey All,

I may have missed this in the rules somewhere, but I had an interesting occurrence in one of my games.

I had a Barricade token in a space, and also an Investigator with the 2x4 item. There were a hoard of monsters on the other side of the door, so I spent one action to put the Barricade in place over the door, and then did the Trade Action to drop the 2x4 to "brace the Barricade" .

I have found nothing that specifically precludes this, but then it begs the question: "How do we treat double Barricades?"

I have been house ruling this that the door is double-barricaded. In other words, when monsters try and move through the door, they role their Brawn and if they succeed, one of the Barricades is destroyed. But then they have to role for the second one, and also destroy that one, in order to move. If they succeed on the first but not the second, then for all subsequent monsters, it is as the normal rules for Barricades (only one present) that they have to break through.

Thematically, this is like throwing the sofa over the door, and then piling up more junk behind it to brace it even further.

Anyone else run across, this or know where in the Rules as Written (RaW) I am doing this incorrectly?

Cheers!

This isn't directly covered.

I tend to like to make things harder so I would rule that a double barricade gets pulled down just as easily as a single one.

I could make an argument that the wording on the barricade doesn't care if there is one barricade or 20 there, its still one item to overcome but it would be based on as much assumption as it would be on hard facts.

Here is the closest I have found, which can be interpreted to mean that as long as a monsters rolls the 2 successes, it moves. It can also be interpreted to mean it moves and runs into another barricade. Heck there are probably 4 ways I could interpret it, all equally valid.

This depends a bit on how the logical chains are supposed to be linked. Is it?

IF the monster rolled two or more success results

THEN Barricade is discarded

THEN monster moves as normal

ELSE the monster forfeits its movement

If so, when you have two barricades, the Monster would try to do a normal move through it but roll dice to break it down.

If the first roll succeeds, barricade 1 would be discarded. Step two would be to continue the normal move, which would allow the monster to try and break down barricade 2. As soon as it fails a test, its movement would be forfeit, meaning it could not try and break down more barricades.

I agree with totgeboren.

The rules as they are adequate enough.. A normal move includes checking for a barricade. If one barricade is knocked down, then move normally (and check again for a barricade) and so on.

Another way to think of it.. if the monster had enough moves to move through two individual doors (both barricaded).. would you expect to roll to beat each barricade individually (so, up to twice)? Of course you would.. no different for two barricades in a single door.

Agreed with Totgeboren. You resolve effects one at the time, so that you first have monster vs barrier; if monster passes, then check what's next. Another barrier? Good, then resolve again monster vs barrier

This would also mean that a monster that tries to break down a barricade, but fails on the first try would no be able to have a go at the second barricade in the same round.
Breaking down barricades is part of the monster movement, so as soon as a "forfeits its movement" condition triggers, it can't break down barricades.

Thanks for the insights and replies everyone.

That is exactly how I am running this already, so it is good to get some confirmation out there.

Cheers!

So, would this also mean that it would take an Investigator two actions to remove two barricades from a single door?

22 hours ago, [Gamemaster] said:

So, would this also mean that it would take an Investigator two actions to remove two barricades from a single door?

Seems only fair...