I find this game fascinating and would love it if anyone could explain some of the math behind it.

Example: if you're rolling 6 dice and you need to get three separate and different results at the same time, how do you figure that? I know you have a 16% chance of rolling a single result, and if you roll 6 dice you multiply that by 6 which would equal 96%. But, if you have to get 2 different results, do you just cut that number in half equaling 48%? Then if you needed three different results would you divide 96% by 3, equaling 32%?

Following this same formula, if you miss on the first shot and now only have 5 dice it would be 26%, 4 dice would be 21%, 3 dice would be back down to 16%.

Did I get that right?

To further complicate the question, say you have to roll 2 tentacles and 1 skull with 6 green dice, how would you calculate that? It's not like the above situation with three different results, two of the dice MUST match, and one MUST NOT.

You may want to check this file here : https://boardgamegeek.com/filepage/118822/math-elder-sign