Can I use curse blood against someone and possible poping their block making my attack unblocakable. Also in the case you get a card effect that rounds down and the trigger number is 1 would it round down to zero. Leader of the Manitou comes to mind right now during my play test session.

cursed blood discard from card pool.

it does NOT cancel its effects.

Usually a foundation played (as a form) in the card pool has no effects. If it was played as a block though, the block effect exists independent of the card in the card pool.

So in short, no.

Well, yes, you can use it to "discard" the block, but no, it does not make your attack unblockable, it just clears your opponents card pool for them.

And yes, half of 1, rounded down, is 0.

congratulations to me for reading half of your question, lol.

But yeah, half of 1 rounded down is zero.

Incidentally .999999 (going on forever) is actually equal to 1......wowzers

Smazzurco said:

.9999 repeating rounded down is 0.

.9999 repeating is not 1, but it is close enough as makes no difference.

let X = .9999(repeating)

then 10x is ten times that...we all know when multiplying by 10 you just move the decimal one place to the right....so 10x = 9.9999(repeating)

So then 10x - x = 9.999(repeating) - .999(repating)

So then 9x = 9

So then X = 1

Going back to the top .9999(repeating) = X = 1 thus .999(repeating) = 1

All your base are belong to ME

Smazzurco said:

That would work all fine and dandy if you could indeed multiply a repeating number by 10, which you really can't.

Assume that the .999 repeating has an end 10,000,000,000,000 digits from here. Multiplying by 10 WILL move a decimal point to the right, but the result will leave a bit fat zero as the last digit. This, your 9x=9 would actually be 9x = 8.999 repeating with 10,000,000,000,000 digits later, which divided by 9 would yield...

x = 0.999 repeating with 10,000,000,000,000 more 9's. Ohbahgawd!

Nice try, though.

guitalex2008 said:

Whats 10 times 2/3rds?

that's right, its 6-2/3rds.

Pretty sure that's multiplying a repeating decimal (.666repeating) times 10.

thanks for playing

Smazzurco said:

Not really. That's multiplying a fraction by 10.

Why are we discussing this again?

edit: Looked it up. Weird as hell, but sure.

Turns out if we expand 0.999... as an infinite series we have 0.9 + 0.09 + 0.009 + ... which is 9*(1/10) + 9*(1/10)^2 + 9*(1/10)^3 ... so we have 9 * sum ((1/10)^n), which expands to 9 * (1/10)/(1-(1/10)) which is 9* (1/10)/(9/10) = 9* (1/9) which is equal to 1.

The easier way to see it is 1/3 = 0.3333333... so 3 times that equation is 1 = 0.99999... so as a result... Cursed Blood doesn't negate blocks!

edit2: Found a really bad joke.

How many mathematicians does it take to screw in a light bulb? 0.999...

guitalex2008 said:

My brain just exploded. Thanks for that, y'all.

here guys, this one is very very easy

8.3.2.10 If a block is discarded from the card pool before the Damage Step. Then the
attack will still be considered blocked since the block quality was established and
the attack took on the completely or partially blocked status during the Block
Step.

so the people that did not know that .999~=1 haven't taken basic calculus? because that's integral in proving derivatives

Ziephnir said: