Tournament tie breaker question

By OpT1mUs, in General Discussion

So last weekend we had our first agot 2.0 tournament, 12 people. It was pure 4 round swiss without the cut. By the end we had a 4 - 0 winner, and three of us were tied with 3 - 1. One of the guys who organized the torney was one of us three. SoS was like this (simplified e. g.),

player A : 14

player B : 13

player C : 12

He ruled player A as first place (in the tied group) , but then ruled player C second because he beat player B during swiss.

Reading the tournament rules, it says that the head to head tie breaker is : If one player has beaten ALL other tied players then he gets advantage, otherwise it goes to the second tie breaker which is pure SoS, which would make player B above player C.

So, if anyone understood the question, was the organizer in the wrong to have the tied players in the final order

player A

player C

player B

instead of

player A

player B

player C