Expected damage of the X-Wing = [ 3 * (1 hit result ) + 1 * (2 hit result) + 2 * (1 crit result) ] / 8 = 0.75
Math question...would the statistics really work that way since the X-Wing is less likely to land a hit in the first place?
The A-Wing may actually be a better all around fighter than the X-Wing. When it comes to anti ship dice, the black dice actually has a better chance of doing one damage than the X-Wing's Red dice with bomber (2 blanks and one accuracy on the red die, only two blanks on the black die, and crits don't exist without a hit icon on the black die so lack of bomber isn't really a detriment). Granted the X-Wing will give you better quality damage with critical effects but it is less likely to do damage in the first place.
Average damage output for Bomber Red vs non-Bomber Black is actually the same because of the Red die's HH result. Both have a total of 6 damage available to them on the die. The black die will be more consistent (only results are 0 or 1 damage) compared to the red die's expected output of 0, 1, or 2.
-Edit - maybe I should rephrase that as the X-Wing is more likely to roll a blank (or accuracy)...
Expected damage of an A-wing = [4 * (hit result) + 2 * (hit/crit result but we ignore the crit)] / 8 = 0.75
In this case it would. Granted, the X-wing has a 1 in 4 chance of dealing a critical effect as well.
Maybe I'm misremembering this, I don't actually have the dice in hand, but doesn't the Black die have 2x Hits 2x Crits 2x Hit+Crit and 2x Blank? Everyone here that is taking major exception to my A-wing bash keeps assuming the chance for a hit is equal at 75%, but if the A-wing's Black Die is actually =[2*(hit result)+2*(Hit+Crit)]/8=0.5
Again, I'm going by memory and pics off a Google search, but i clearly remember Black having the Crit only results.
RED: 2 Blanks, 1 Accuracy, 2 Hit, 1 Hit+Hit, 2 Critical
BLUE: 2 Accuracy, 4 Hit, 2 Critical
BLACK: 2 Blank, 4 Hit, 2 Hit+Critical