Hi All,

Managed to confuse myself on the final battle wording, was hoping someone could provide clearer guidance!

How exactly do the dice rolls add?

Example one (how I hope it works)

4 players fighting the AO

1) Player 1 scores 3 successes - these are recorded

2) Player 2 scores 5 successes - the AO takes 2 doom markers from the track.

3) Player 3 takes a turn....

Example 2 (how I feel the rules might be interpreted)

4 players as before

1) Player 1 scores 3 successes - as before

2) Player 2 scores 5 successes - the AO takes 1 doom marker from the track (1 success is added to the prior 3, making enough to remove a doom marker, then the count is re-set, so the other 4 successes are wasted....)

Azazel1

The easiest way to calculate how many successes you need to defeat the Ancient One is multiply the number of players by the number of tokens...thus, an AO with an 11 Doom Track and 4 Players will require 44 successes.

If , as you had in your example, Player 1 yielded 3 successes, and Player 2 yielded 5 more successes, remove two tokens, ad the successes carry-over from one player to the next.

Cheers,

Joe

Yup, what Joe said. Unfortunately, the rulebook it's oddly worded on this point, too many over the years (including myself) asked about this.

Also, remember that if someone is devoured during final battle (or immediately after the AO awakens because he was LiTaS), you still count him in the number of investigators. So, 4 investigators playing, 2 devoured, you still need 4 successes / token.

Great - thanks for the confirmation! Beat Yig at the weekend this way, and didn't want to think we had somehow cheated! :-)

Yig is the easiest AO to beat in final combat. You won't be so fortunate next time

yea, you should try facing Azathoth in the final battle, he can be a really hard customer in that regard!